6x^2+1.5x-10.25=0

Solution for 6x^2+1.5x-10.25=0 equation:

6x^2+1.5x-10.25=0

a = 6; b = 1.5; c = -10.25;
Δ = b2-4ac
Δ = 1.52-4·6·(-10.25)
Δ = 248.25
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1.5)-\sqrt{248.25}}{2*6}=\frac{-1.5-\sqrt{248.25}}{12}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1.5)+\sqrt{248.25}}{2*6}=\frac{-1.5+\sqrt{248.25}}{12}
$